Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.
How can the electric force between two charges q1 and q2 be doubled?
Justification: The electric force one charge exerts on another is directly proportional to the product of the two charges, and thus is also proportional to each individual charge. If the magnitude of one charge is doubled then the magnitude of the force is also doubled.
What happens to the force between two charges when the distance is doubled and halved?
Explanation: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
What happens to force when charge doubles?
The law says that the force is proportional to the amount of charge on each object and inversely proportional to the square of the distance between the objects. If we double the charge q 1 , for instance, then the force is doubled.
Which of the two charges Q1 and q2 is greater in magnitude?
From the graph, it can be seen that net potential due to the two charges is positive everywhere in the region left of charge Q1. Therefore, the magnitude of potential due to charge Q1 is greater than that due to Q2. Therefore, the absolute value of charge Q1 is greater than that of Q2.
What is the force applied between Q1 and q2?
q2 is positive (in case of like charges), the force F is positive and pushes the charges away from each other. The product q1. q2 is negative for unlike charges and the force F is negative. This means the objects are attracted to each other.
What is the electric force between two charges when the distance between them is reduced to half its original value?
If the distance between two charges is reduced by half then the force between the two charges is quadrupled.
What is the force between an electron and an alpha particle separated by a distance 2?
hence, magnitude of force between electron and alpha particle is 4.608 × 10^-8 N.
How does quadrupling the distance between two objects affect the gravitational force between them?
How does quadrupling the distance between two objects affect the gravitational force between them? … The gravitational pull this time would decrease approximately like nine times since you would square the one-third to get one-ninth.
How would the electric field at that point be affected if the charge there were doubled?
(b) How would the electric field at that point be affected if the charge there were doubled? Would the magnitude of the electric force be affected? of the ratio i.e. the electric field would be unchanged.
How do you find the force between two charges?
The direction of the force vector depends on the sign of the charges. If the charges are the same, the force points away from the other charge. If the charges have different signs, the force points toward the other charge((Figure)).
What factors affect electric force between two objects?
As we’ll discuss in this lesson, he found that the force between charged particles was dependent on only two factors: the distance between the particles and the amount of electric charge that they carried.
What is the nature of force between two charges q1 and q2 such that they are q1q2 0 and q1q2 0?
if Q1>0, then Q2 <0. So, Q1 and Q2 and opposite charges. The nature of force between them will be attractive. Opposite charges attract each other.
What is the nature of force between two charges q1 and q2 if?
The electric force between q1 and q2 is directly proportional to the product of the magnitude of charge q1 and q2 and is inversely proportional to the square of the distances between their centres.
What is the nature of electrostatic force between two point charges q1 and q2 if q1 q2 0?
The electrostatic force is repulsive when q1 q2 > 0, i.e. the two charges have the same signs (either both positive or both negative). The electrostatic force is repulsive when q1 q2 > 0, i.e. the two charges have the same signs (either both positive or both negative).