Your question: Why does inside the spherical cavity electric field is zero?

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As there is no charge inside the cavity, no charge is enclosed by Gaussian sphere, so electric flux is zero, hence electric field is zero.

Why is the electric field inside a sphere zero?

It is because charge doesn’t reside inside it, it moves outside the surface of it producing electric field inside zero. Because at any point inside the spherical shell the total charge enclosed is zero.

Is the electric field inside a cavity zero?

The electric field inside a cavity is only zero if the cavity contains no charges.

What is the electric field inside the sphere?

In case of a hollow spherical shell, the electric field inside the shell is zero .

Is the electric field inside a cavity zero even if the shell is not spherical?

Yes, the electric field inside the cavity is zero even when the shape is irregular and not the sphere.

Why is there no net electric field in the empty cavity of a hollow conductor?

Since in the formula q=0 as all charge will be outside the gaussian surface i.e. on the sphere itself, therefore electric field inside the sphere will be zero. As in case of hollow sphere, potential remains constant inside it.. That’s why electric field is zero.

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What is the electric field inside a non conducting solid sphere?

Therefore electric field inside a uniformly charged non- conducting spherical shell is zero.

Is the electric field inside a cavity with no charge zero independent of the fact?

(b) Is the electric field inside a cavity (with no charge) zero; independent of the fact whether the shell is spherical or not? Explain. then, Therefore according to Gauss’s law electric field is zero and it is independent of the fact whether the shell is spherical or not.

What is the electric field in the cavity if a conductor having a cavity is charged does the result depend on the shape and size of cavity of the conductor?

This phenomenon is called electrostatic shielding. Hence net electric field is zero inside the cavity in a conductor, irrespective of shape, size or location of the cavity. Note: This result is true for any shape and size of conductor.