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A conduction disorder is a problem with the electrical system that makes your heart beat and controls its rate and rhythm. This system is called the cardiac conduction system. Normally, the electrical signal that makes your heart beat travels from the top of your heart to the bottom.

## How electric field due to an infinite long straight conductor varies with distance?

Where λ = linear charge density, r = radius of the cylinder, and εo = permittivity of free space. From the above equation, it is clear that the electric field of an infinitely long straight wire is proportional to 1/r. Hence option 1 is correct.

## How the electric field E depends upon the distance r due an infinitely long uniformly charged thin wire?

Electric field due to infinite long charged wire

Since the magnitude of the electric field for the entire curved surface is constant, E is taken out of the integration and Q_{encl} is given by Q_{encl} = λL. The electric field due to the infinite charged wire depends on 1r rather than 1r2 1 r 2 for a point charge.

## What is electric field at a point due to infinitely long thin charge?

2πrlE = λlϵo λ l ϵ o E=12πϵoλr. Therefore, the above equation is the electric field due to an infinitely long straight uniformly charged wire.

## What is electric field intensity due to an infinitely long straight charged wire?

Electric field produced due to an infinitely long straight uniformly charged wire at perpendicular distance of 2cm is 3×108NC−1.

## How does the electric field E vary with distance?

Electric field strength is location dependent, and its magnitude decreases as the distance from a location to the source increases. And by whatever factor the distance is changed, the electric field strength will change inversely by the square of that factor.

## How do electric field varies with distance due to linear charge?

The electric field varies inversely as the square of the distance from the point charge.

## What is the expression for electric field due to dipole at equatorial position?

Let P be a point at a distance r from the center of the dipole on the equatorial line, where the electric field is to be calculated. Let E_{1} be electric field intensity at P due to charge –q. Therefore, From right-angled triangle AOP, we have AP = √r^{2} + a^{2} .

## When an electric dipole P is placed in a uniform electric field E?

An electric dipole of moment P is placed in a uniform electric field E such that P points along E . If the dipole is slightly rotated about an axis perpendicular to the plane containing E and P and passing through the centre of the dipole, the dipole executes simple harmonic motion.

## What is the potential energy due to dipole in an external electric field?

The potential energy of a dipole in an external field

τ = p × E. This work is saved as the system’s potential energy. The potential energy U(θ) can then be linked to the dipole’s inclination θ.

## Which law is used to find electric field at any point near the infinitely long straight uniformly charged wire state this law obtain expression for it?

State Gauss’ law. Using this find an expression for electric field due to an infinitely long straight charged wire uniform charge density.

## What is electric field due to a straight wire?

Consider a long straight wire which carries the uniform charge per unit length. . We expect the electric field generated by such a charge distribution to possess cylindrical symmetry. We also expect the field to point radially (in a cylindrical sense) away from the wire (assuming that the wire is positively charged).

## What is the electric field at the midpoint O of the line AB joining the two charges?

O is the mid-point of line AB. Therefore, the electric field at mid-point O is 5.4 × 10^{6} N C^{−}^{1} along OB.

## What is the relationship of electric field and electric potential?

The relationship between potential and field (E) is a differential: electric field is the gradient of potential (V) in the x direction. This can be represented as: Ex=−dVdx E x = − dV dx . Thus, as the test charge is moved in the x direction, the rate of the its change in potential is the value of the electric field.

## Which is the correct relation for electric intensity and potential due to a point charge?

The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = – dV/dr.