Question: What is the magnitude of the electric field that will balance the weight of a proton?

What are the magnitude and direction of the electric field that will balance the weight of the following? For an electron/proton we use the equation qE=mg. Therefore the answer for magnitude would just to multiply the mass of an electron/proton by 9.8.

What magnitude of electric field is required to balance the weight of the electron?

The electric force on an electron F= qE where q is the electronic charge and E is the electric field strength. The gravitational force on an electron F = mg where m is the electron mass and g is the graviational field strength -probably you would use 9.81 ms^-2.

What is the magnitude of the electric field that will bring a proton?

Use 1.67×10−27 1.67 × 10 − 27 kg for the mass of a proton, 1.60×10−19 1.60 × 10 − 19 C for the magnitude of the charge on an electron, and 9.81 m/s2 for the magnitude of the acceleration due to gravity.

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What is the direction of an electric field that will balance the weight of an electron?

The force should be directed against weight due to gravity. Thus, the electric field should be directed downwards.

What is the magnitude and direction of an electric field that will balance?

As the direction of electric force on negatively charged particle is opposite to the direction of electric field, the direction electric filed is downward. Hence, the magnitude of electric field is and direction is downwards. Chapter 23, Problem 23P is solved.

What is the magnitude of the electric field in which an electron experiences an electric force equal to its weight?

An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will be 5.5 × 1011 N/C.

What is the charge of an electron in Kollam?

electron charge, (symbol e), fundamental physical constant expressing the naturally occurring unit of electric charge, equal to 1.602176634 × 1019 coulomb.

What is the magnitude of an electric field in which the electric force?

The magnitude of the electric force between q 1 q_1 q1​q, start subscript, 1, end subscript and q 2 q_2 q2​q, start subscript, 2, end subscript is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them. This equation is known as Coulomb’s Law.

What is the magnitude of the electric field strength E such that an electron?

m2e2g.

How heavy is a proton?

proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 1027 kg, which is 1,836 times the mass of an electron.

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How much mass do electrons have?

The rest mass of the electron is 9.1093837015 × 1031 kg, which is only 1/1,836the mass of a proton. An electron is therefore considered nearly massless in comparison with a proton or a neutron, and the electron mass is not included in calculating the mass number of an atom.

What is the orientation of an electric dipole in a uniform?

-The dipole is in stable equilibrium when it is aligned parallel to the electric field (i.e. the angle between the dipole moment and the electric field is 0∘).