Frequent question: What is the direction of the electric field caused by an infinite line charge arranged along the z axis?

What would be the direction of the electric field around an infinite line that has a uniform distribution of positive charge?

The electric field of an infinite line charge with a uniform linear charge density can be obtained by a using Gauss’ law. Considering a Gaussian surface in the form of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward.

What is the electric field due to infinite line of charge?

Yes, an electric field can be zero. For unlike charges, the electric field is zero outside when the magnitude of the charge is small. For like charges, the electric field is zero along the line joining the two charges.

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What is the direction of the electric field on a line of charge?

The direction of the electric field is always directed in the direction that a positive test charge would be pushed or pulled if placed in the space surrounding the source charge. Since electric field is a vector quantity, it can be represented by a vector arrow.

How does the electric field due to an infinite line of charge depend on the distance to the line?

if you have a point r distance above the end of the line, as the distance increases the electric field would decrease because the “ends” behave like point charges.

What is the outward electric flux through the cylinder?

Thus, flux through the side of the cylinder is 0. (c) Net outward flux through side of the cylinder: This flux is due to the surface 1 and 2. Thus, the net outward flux through side of the cylinder is 3.14 $N{m^2}{C^{ – 1}}$.

What is the electric field outside the hollow cylinder?

Using Gauss’ law the electric field outside the charged cylinder is identical to the field of a line charge with an equivalent charge density given by the equation. where r = radius of the cylinder, is the surface charge density (C /m^2) and is the equivalent linear charge density (C/m).

What is equation of an electric field intensity due to an infinitely long straight wire?

Since the magnitude of the electric field for the entire curved surface is constant, E is taken out of the integration and Qencl is given by Qencl = λL. The electric field due to the infinite charged wire depends on r rather than r 1 r 2 for a point charge.

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What is the electric field due to a long straight wire?

Gauss law is a very important part of electromagnetism and physics. It is used to relate the distribution of charge with the resulting electric field due to the charge. This law was formulated by Joseph Lagrange in 1773, followed by Carl Gauss in 1813.

How do you find the direction of the electric field?

For example, if you place a positive test charge in an electric field and the charge moves to the right, you know the direction of the electric field in that region points to the right.

What is the direction of electric field Class 12?

The direction of electric field produced by positive charges is radially outward from the charge, i.e. away from the point charge. The direction of electric field produced by negative charges is radially toward the charge, i.e. towards the point charge.

Does the electric field due to an infinitely long line charge depend on the distance of observation point from the line charge if yes how?

The electric field due to an infinite plane sheet of charge does not depend upon the distance of the observation point from the plane sheet of charge.

How does the electric field due to an infinite wire of charge fall off as a function of the distance r?

The E field intensity falls of as 1/r². An infinite line charge distribution (if it is a uniform distribution) has cylindrical symmetry. This is because for every point Arbitrary point P in space, there are exactly two points a distance d away from point P, one in each direction.

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